在线英语听力室

英语听力:自然百科 穿越银河系的旅行 Through Milky Way—18

时间:2014-05-27 07:09:05

搜索关注在线英语听力室公众号:tingroom,领取免费英语资料大礼包。

(单词翻译)

 Measuring the brightnesses and colors of the stars in the globular cluster, we can figure out how old they are. Here is the remarkable1 thing: they are very old. Globular clusters, at least the stars in the globular clusters, in many cases, are almost as old as the universe itself. 

 
 
 
Globular clusters are like living fossils. It’s like discovering a community of people who’s been around since the Stone Age. Some stars here have been shining for 12 billion years, more than twice as long as the sun and that helps to put an age to the Milky2 Way. 
 
 
 
Globular clusters are part of our galaxy3. They orbit our galaxy, in some sense, they are tracers of our galaxy itself. And so by the fact that the globular clusters are so old, it suggests that the galaxy is so old. 
 
 
 
So globular clusters tell us something extraordinary. Our galaxy is one of the oldest objects in the cosmos4. It’s been around almost since the beginning of the universe, at least 12 billion years. The stars in these clusters also reveal/ that when it first formed, the chemistry of the galaxy was very different from how it is today. 
 
 
 
We can measure the chemical properties of those stars. Turns out, they have very low abundances of the heavy elements, things like iron, are very rare in globular cluster stars compared to a star like the sun. 
 
 
 
What’s true of / globular clusters is true of the early galaxy. It would have been a far less colorful place, lacking heavy elements which color the nebulae and supernovae remnants we see today. But more importantly, it would have been a galaxy without life. It took billions of years for stars to form enough heavy elements for the evolution of life to begin anywhere in the Milky Way.

分享到:

Error Warning!

出错了

Error page: /mobile/index.php?aid=260164&mid=3
Error infos: Got error 28 from storage engine
Error sql: select `l`.`tag`,`l`.`index`,`l`.`level_id`,`b`.`id`,`b`.`word`,`b`.`spell`,`b`.`explain`,`b`.`sentence`,`b`.`src` from `new_wordtaglist` `l` left join `new_word_base` `b` on `l`.`tag`=`b`.`word` where `l`.`arc_id`='260164' and `l`.`level_id`>='' group by `b`.`word` order by `l`.`index` asc

本文本内容来源于互联网抓取和网友提交,仅供参考,部分栏目没有内容,如果您有更合适的内容,欢迎 点击提交 分享给大家。